mensuration for competitive exams mensuration problems

mensuration for competitive exams

mensuration mock test

mensuration mock test for preparation of competitive exams

Question 1 of 5

1. Question
The perimeter of a rectangle is 42 m. If the area of the square formed on the diagonal
of the rectangle as its side is 1 1/12 % more than the area of the rectangle, find the
longer side of the rectangle
- 19 m
- 16 m
- 9 m
- 5 m
- 12 m
Correct

12m is answer

Incorrect

12m is answer

Hint

12m is answer is correct
Question 2 of 5

2. Question
At the rate of Rs. 2 per sq m, cost of painting a rectangular floor is Rs 5760. If the length of the floor is 80% more than its breadth, then what is the length of the floor?
- 25 m
- 72 m
- 67 m
- 56 m
- 46 m
Correct

Let the length and the breadth of the floor
be l m and b m respectively.
l = b + 80% of b = l + 0.8 b = 1.8b
Area of the floor = 5760/2 = 2880 sq m
l*b = 2880 i.e., l * l/1.8 = 2880
l = 72

Incorrect

Let the length and the breadth of the floor
be l m and b m respectively.
l = b + 80% of b = l + 0.8 b = 1.8b
Area of the floor = 5760/2 = 2880 sq m
l*b = 2880 i.e., l * l/1.8 = 2880
l = 72
Question 3 of 5

3. Question
A 7 m wide path is to be made around a circular garden having a diameter of 7 m.
What will be the area of the path in square metre?
- 298
- 256
- 308
- 365
- 387
Correct

Area of the path = Area of the outer circle –
Area of the inner circle = π{7/2 + 7}2 – π[7/2]2
= 308 sq m

Incorrect

Area of the path = Area of the outer circle –
Area of the inner circle = π{7/2 + 7}2 – π[7/2]2
= 308 sq m

Hint

308 is correct answer. Find Solution or Explanation at the end of Quiz.
Question 4 of 5

4. Question
The perimeter of a rectangle of length 62 cm and breadth 50 cm is four times
perimeter of a square. What will be the circumference of a semicircle whose
diameter is equal to the side of the given square?
- 25 cm
- 36 cm
- 29 cm
- 17 cm
- 16 cm
Correct

Let the side of the square be a cm.
Parameter of the rectangle = 2(62 + 50) =
224 cm Parameter of the square = 56 cm
i.e. 4a = 56
So a = 14
Diameter, d of the semicircle = 14 cm
Circumference of the semicircle = 1/2(π)(r)+ d
= 1/2(22/7)(7) + 14 = 25 cm

Incorrect

Let the side of the square be a cm.
Parameter of the rectangle = 2(62 + 50) =
224 cm Parameter of the square = 56 cm
i.e. 4a = 56
So a = 14
Diameter, d of the semicircle = 14 cm
Circumference of the semicircle = 1/2(π)(r)+ d
= 1/2(22/7)(7) + 14 = 25 cm

Hint

25 cm is correct answer. find solution (explanation) at the end of Quiz.
Question 5 of 5

5. Question
A cone with diameter of its base as 30 cm is formed by melting a spherical ball of
diameter 10 cm. What is the approximate height of the cone?
- 6 cm
- 3 cm
- 2 m
- 5 cm
- None of these
Correct

Radius of cone = 30/2 = 15, radius of ball = 10/2 = 5
Volumes will be equal, so
$(1 / 3) {πr}^{2} h = (4 / 3) {πr}^{3} 15^{2} h = 4 * 53 so h = 2.2$

Incorrect

Radius of cone = 30/2 = 15, radius of ball = 10/2 = 5
Volumes will be equal, so
$(1 / 3) {πr}^{2} h = (4 / 3) {πr}^{3} 15^{2} h = 4 * 53 so h = 2.2$

Hint

2 m is correct answer. find solution (explanation) at the end of Quiz.

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